2x + 1 > 0 (1)
log(x^2) (2x+1) = 1/2
(x^2)^(1/2) = (2x+1)
±x = 2x + 1
x1 = - 1/3
x2 = - 1/2 (不符合(1)式,舍弃)
所以,方程的解为 x = -1/3 .