问几个分式化简的问题:a2-ab/b2-ab x2+x/x2-1 x2+4x/x2+8x+16 x2-2x/2y-xy
人气:330 ℃ 时间:2020-06-08 02:52:12
解答
(a²-ab)/(b²-ab)= a(a-b)/b(b-a)=-a/b(x²+x)/(x²-1)=x(x+1)/(x+1)(x-1)=x/(x-1)(x²+4x)/(x²+8x+16)=x(x+4)/(x+4)²=x/(x+4)(x²-2x)/(2y-xy)=x(x-2)/y(2-x)=-x/y
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