∵数列{cn}的通项是cn=4n+312n−1，∴c1＝4+312−1=35，c2＝8+314−1=13，c3＝12+316−1=435，c4＝16+318−1=477，c5＝20+3110−1=519，c6＝24+3112−1=5，∵{cn}是减数列，∴假设cn=4n+312n−1=4成立，则4n+31=8n-4...