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1.数列{(2n-3)/2^(n-3)}的前n项和为
A.4-((2n-1)/2^(n-2))
B.4+((2n-7)/2^(n-2))
C.8-((2n+1)/2^(n-3))
D.6-((3n+2)/2^(n-2))
人气:351 ℃ 时间:2020-01-30 05:15:32
解答
Csn=-1/2^(-2)+1/2^(-1)+3/2^0+...+(2n-5)/2^(n-4)+(2n-3)/2^(n-3)(1/2)sn=-1/2^(-1)+1/2^0+3/2^1+..+(2n-5)/2^(n-3)+(2n-3)/2^(n-2)1/2 sn=-1/2^(-2)+2[1/2^(-1)+1/2^0+1/2^1+1/2^(n-3)]-(2n-3)/2^(n-2)1/2 sn...
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