图示为一简谐横波在某时刻的波形图,已知波速为2.4m/s,试问:(1)此简谐横波的周期为
图示为一简谐横波在某时刻的波形图,已知波速为2.4m/s,试问:(1)此简谐横波的周期为多少?(2)在2s时间内这列横波向前传播了多少距离?
↑ˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉ
10 |
|
|
0 |ˉˉ0.3ˉ0.6ˉ0.9ˉ1.2ˉˉˉˉˉˉ
-10ˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉ
经过10 0.3 0.9 曲线!10开始向下连到0.3 然后绕过0.
人气:173 ℃ 时间:2020-05-01 05:40:04
解答
(1).0.9=(3/4)倍波长,波长=1.2,周期=波长/波速=1.2/2.4=0.5(s)
(2)在2s时间内这列横波向前传播的距离= 波速*时间=2.4*2=4.8(m)
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