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(1)已知1/X-1/Y=3,求分式(2X+3XY-2Y)/(X-2XY-Y)的值.
(2)化简:(x的二次方-2xy+y的二次方-1)/(x-y-1)=
人气:409 ℃ 时间:2020-03-24 13:45:13
解答
(1)∵1/X-1/Y=3∴y-x=3xy分式(2X+3XY-2Y)/(X-2XY-Y)=[-2﹙y-x﹚+3XY]/[-﹙y-x﹚-2XY]=﹙-6XY+3XY﹚/﹙-3xy-2xy﹚=﹙-3xy﹚/﹙-5xy﹚=3/5(2):(x的二次方-2xy+y的二次方-1)/(x-y-1)=﹙x...
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