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求一道一元二次题目的解法全过程
(4x-1)²-10(4x-1)-24=0
人气:144 ℃ 时间:2020-09-17 05:04:21
解答
(4x-1)²-10(4x-1)-24=0
(4x-1)²-10(4x-1) + 25-25-24=0
((4x-1)-5)²-49 = 0
((4x-1)-5)² = 49
(4x-1)-5 = ±7
x = 3.25 或 x = -0.25
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