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(x-1)/(x+3x+2)+6/(2+x-x)-(10-x)/(4-x)
人气:231 ℃ 时间:2020-02-03 20:18:23
解答
(x-1)/(x^2+3x-2)+6/(2+x-x^2)-(10-x)/(4-x^2) =(x-1)/[(x+1)(x+2)]-6/[(x+1)(x-2)]-(x-10)/[(x+2)(x-2)] =(X^2-3X+2-6X-12-X^2+9X+10)/[(X+2)(X+1)(X-2)] =0
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