lny=sinxln(x²+3x+6)对x求导(1/y)*y'=cosxln(x²+3x+6)+sinx*1/(x²+3x+6)*(2x+3)所以y'=(x²+3x+6)^sin*[cosxln(x²+3x+6)+sinx*(2x+3)/(x²+3x+6)]