(2)∵函数f(x)的定义域为{x|x≠0}.
∴定义域关于原点对称,
则f(x)=(
1 |
ax−1 |
1 |
2 |
ax+1 |
2(ax−1) |
∴f(-x)=
a−x+1 |
2(a−x−1) |
1+ax |
2(1−ax) |
ax+1 |
2(ax−1) |
∴f(x)是偶函数;
(3)∵f(x)是偶函数;
∴f(x)>0在定义域上恒成立,
则只需要当x>0时,f(x)>0恒成立即可,
即f(x)=
ax+1 |
2(ax−1) |
∴ax-1>0,
即ax>1,
∵x>0,
∴a>1,
即求a的取值范围是a>1.
1 |
ax−1 |
1 |
2 |
1 |
ax−1 |
1 |
2 |
ax+1 |
2(ax−1) |
a−x+1 |
2(a−x−1) |
1+ax |
2(1−ax) |
ax+1 |
2(ax−1) |
ax+1 |
2(ax−1) |