答：(1+w)^4=(1-w)^4(1+w)^4-(1-w)^4=0[ (1+w)^2+(1-w)^2 ] * [ (1+w)^2-(1-w)^2 ]=0(1+2w+w^2+1-2w+w^2)*(1+2w+w^2-1+2w-w^2)=0(2w^2+2)*(4w)=0(w^2+1)w=0解得：w=0或者w^2+1=0所以：w=0或者w= i 或者w= - i...