实验室需要配制500g质量分数为10%的盐酸需要质量分数38%的浓盐酸(密度为1.19克/cm3)多少ml?水多少ml?
人气:453 ℃ 时间:2019-08-17 17:29:05
解答
需要浓盐酸110.6mL,需要水的体积是386.4mL500g质量分数为10%的盐酸溶质质量=500*10%=50g需要38%浓盐酸的质量=50/38%=131.6g需要浓盐酸的体积V=m/ρ=131.6/1.19=110.6mL需要水的质量是500-131.6=368.4g因为水的密度是...
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