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1+tana/1-tana=2006 则1/cos2a +tan2a
人气:248 ℃ 时间:2020-06-03 05:47:23
解答
(1/cos2a)+tan2a
=(1/cos2a)+sin2a/cos2a
=(1+sin2a)/cos2a
=(sina+cos)²/(cos²a-sin²a)
=(sina+cos)/(cosa-sina)
=(1+tana)/(1-tana)=2006
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