计算[√3/2+(1/2)i]¹⁵怎么算,r=√[(√3/2)²+(1/2)²]=1；tanθ=(1/2)/(√3/2)=1/√3=√3/3,故θ=π/6;于是原式=[cos(π/6)+isin(π/6)]¹⁵=cos(15π/6)+isin(15π/6)=cos(5π/2)+isin...