hello!^-^令u=2x-π/6,则f（x）=sin(2x-π/6)=sinu=fu).因为-π/12≤x≤π/2,所以-π/3≤2x-π/6≤5π/6,即-π/3≤u≤5π/6.所以根据函数图像可知函数在u∈[-π/3,π/2]上是增函数,在u∈[π/2,5π/6]上是减函数.而f...