将A、B两点的坐标值分别代入y=kx+b解得：k=(3/2)(√3-1)；b=(3/2)(3-√3)函数y=kx+b的解析式为：y=(3/2)(√3-1)x+(3/2)(3-√3)由题可得以下不等式组：(3/2)[(√3-1)x+(3-√3)]＞0=(3/2)[(√3-1)x+(3-√3)]≤x+3x+3＞...