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三道计算题(-2y^2-3x)(3x-2y^2) -(3m^2-n)(3m^2+n) (1/2a^m-b^n)(b^n+1/2a^m)
人气:153 ℃ 时间:2020-10-01 05:19:31
解答
(-2y^2-3x)(3x-2y^2)
=4y^4-9x^2
-(3m^2-n)(3m^2+n)
=-9m^4+n^2
(1/2a^m-b^n)(b^n+1/2a^m)
=1/4a^2m-b^2n
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