已知x²+y²-6x-8y+25=0,求y分之x-x分之y的值
人气:203 ℃ 时间:2020-01-28 21:06:49
解答
有已知条件得:
x²+y²-6x-8y+25=(x-3)²+(y-4)²=0
要想以上式子成立,只能当:x-3=0,y-4=0时才能成立,以此得到:x=3,y=4
求:(x/y)-(y/x)
= -1/4
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