1.x(x-1)(x-2)-6 =x[x^2-3x+2]-6=x^3-3x^2+2x-6=x^2(x-3)+2(x-3)=[x-3][x^2+2]2.1-xy(1-xy)-x^3y^3 =[1-xy][1+xy+x^2y^2]-xy[1-xy]=[1-xy][1+xy+x^2y^2-xy]=[1-xy][1+x^2y^2]3.x^2+4xy+4y^2-2x-4y+1=[x+2y]^2-2[x+2y...