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椭圆kx^2+(k+2)y^2=k的焦点在y轴上,求k取值?
人气:183 ℃ 时间:2020-05-13 15:56:03
解答
椭圆kx^2+(k+2)y^2=k的焦点在y轴上,
kx^2+(k+2)y^2=k
x^2+y^2/[k/(k+2)]=1
焦点在y轴上,
k/(k+2)>1
k/(k+2)-1=-2/(k+2)>0
k+2<0
k<-2
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