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数学
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用洛必达法则求lim(x→0+)cotx/lnx
人气:390 ℃ 时间:2019-08-20 21:33:20
解答
lim(x→0+)cotx/lnx(∞/∞)
=lim(x→0+) -csc^2x/(1/x)
=lim(x→0+) -x/(sin^2x)
=lim(x→0+) -x/x^2
=-∞lim(x→0+) -x/(sin^2x)=lim(x→0+) -x/x^2这步是怎么得到的啊?分别求导?可是(sinx)^2的导数不是sin2x吗?是等价无穷小代换x→0,sin^2x~x^2
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