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数学
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先化简,再求值.已知x=-2,y=125分之一,求x(3x-2y)+(2x+y)²+(2x-y)(x+y)-3(xy+10)的值
人气:477 ℃ 时间:2019-10-23 03:55:35
解答
x(3x-2y)+(2x+y)²+(2x-y)(x+y)-3(xy+10)
=3x^2-2xy+4x^2+4xy+y^2+2x^2+xy-y^2-3xy-30
=9x^2-30
x=-2,
=36-30
=6
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