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已知1/x=1/y+4,求分式(6x+3xy-6y)/(x-y-2xy)的值?
人气:330 ℃ 时间:2020-05-08 02:45:05
解答
1/x=1/y+4 两边乘以xy
y=x+4xy
x-y=-4xy
(6x+3xy-6y)/(x-y-2xy)
=[6(x-y)+3xy]/(x-y-2xy)
=(-24xy+3xy)/(-4xy-2xy)
=-21/(-6)
=7/2
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