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数学
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方程x-1=lnx必有一个根的区间是
人气:331 ℃ 时间:2020-03-22 14:26:11
解答
设f(x)=x-1-lnx
f(1)=0,x=1是方程的根
又f'(x)=1-1/x
x=1时,f'(x)=0,f(x)得最小值f(1)=0
所以f(x)根有且只有一个x=1
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