已知实数a,b满足等式a方+4b方-a+4b+4分之5=0,求-ab的平方根
人气:433 ℃ 时间:2019-08-18 12:03:28
解答
a^2+4b^2-a+4b+5/4=0
(a-1/2)^2 + (2b+1)^2 = 0
a=1/2,b=-1/2
(-ab)={-(1/2) *(-1/2)} = 1/4
(-ab)的平方根 = ±1/2
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