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cos2x=3/5.sin^4+cos^4x=?
人气:469 ℃ 时间:2020-04-25 22:46:03
解答
(sinx)^4+(cosx)^4
=[(sinx)^2+(cosx)^2]^2-2(sinx)^2(cosx)^2
=1-(1/2)[sin(2x)]^2
=1-(1/2)[1-cos(2x)^2]
=1-(1/2)[1-(3/5)^2]
=1-8/25
=17/25
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