两个自然数的和与差的乘积是1996,则这两数的和是______.
人气:283 ℃ 时间:2019-08-16 23:17:46
解答
设两个自然数为a、b,依题意得
(a+b)(a-b)=1996,且(a+b)、(a-b)的奇偶性相同,
故1996=998×2,
又(a+b)>(a-b),
∴a+b=998.
故本题答案为998.
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