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30分钟,
(1)a^2-4/a+2÷(a-2)x1/a-2
(2)x^2/x-2-x-2
(3)(a+2/x-x+1/x-2)÷x+4/x^2-2x
第三题写错了是:
{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)
人气:437 ℃ 时间:2020-05-08 12:33:13
解答
(1)、[(a^2-4)/(a+2)]÷[(a-2)x1/(a-2)]
=[(a+2)(a-2)/(a+2)]÷1
=a-2;
(2)、x^2/x-2-x-2=x-2-x-2=-4;
(3)、{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)
=[(x+2)/x-(x+1)/(x-2)]÷(x+4)/(x^2-2x)
=[(x+2)(x-2)-x(x+1)]/(x+4)
=-1.
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