已知弧长为C=2336.2,弦长为L=1499.9,怎么样求它是几分之几圆?
弧半径为R,弧所对的圆心角为A.
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=800
R1=741.82
R2=749.82
R3=750.02
R4=750.02
R=750.02
A=C/R=2336.2/750.02=3.11485弧度
它是几分之几圆=A/PI=3.11485/PI=0.9915=9915/10000=1983/2000