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.先化简,在求值4(3x^2y-xy^2)-2(xy^2 3x^2y).其中,x=1/2.,y=-1
人气:217 ℃ 时间:2020-02-03 07:54:39
解答
4(3x^2y-xy^2)-2(xy^2-3x^2y)
=12x^2y-4xy^2-2xy^2+6x^2y
=18x^2y-6xy^2
=6xy(3x-y)
当x=1/2,y=-1时,原式=6*(1/2)*(-1)*(3/2+1)=-25/2
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