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(1)2(4x-0.5) (2)-3(1-六分之一乘x)
(3)负x+(2x-2)-(3x+5) (4) 3a^2+a^2-(2a^2-2a)+(3a-a^2)
人气:153 ℃ 时间:2020-04-24 12:00:58
解答
(1)2(4x-0.5)
=2*4x-2*0.5
=8x-1
(2)-3(1-1/6*x)
=-3*1+3*1/6x
=-3+x/2
(3)-x+(2x-2)-(3x+5)
=-x+2x-2-3x-5
=-2x-7
(4) 3a^2+a^2-(2a^2-2a)+(3a-a^2)
=3a^2+a^2-2a^2+2a+3a-a^2
=a^2+5a
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