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计算:定积分∫(在上1 ,在下√2/2 )(√1-X^2)/x^2 dx求详细过程答案,拜托大神...
人气:225 ℃ 时间:2020-03-30 12:23:17
解答
令x=sint,则dx=cost dt∫(√2/2→1)√(1-x²)/x²dx=∫(π/4→π/2)cost/sin²t·costdt=∫(π/4→π/2)cos²t/sin²t dt=∫(π/4→π/2)cot²t dt=∫(π/4→π/2)(csc²t-1)...
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