y=3sin(2x-π/6)（1）2x-π/6=2kπ+π/2即2x=2kπ+2π/3即 x=kπ+π/3时,y有最大值3,此时x的集合是{x|x=kπ+π/3,k∈Z}（2）增区间2kπ-π/2≤2x-π/6≤2kπ+π/2即2kπ-π/3≤2x≤2kπ+2π/3即 kπ-π/6≤x≤kπ+π...