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[(Xˉy)^2+(x+y)(xˉy)]/x,其中x=1,y=2分之1
人气:265 ℃ 时间:2020-04-06 08:46:18
解答
[(Xˉy)^2+(x+y)(xˉy)]/x
=[x²-2xy+y²+x²-y²]/x
=[2x²-2xy]/x
=2x-2y
=2×1-2×2分之1
=2-1
=1
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