Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1)) 求导数,Y=xloga(x^2+x-1) Y=log2(_数学解答

Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1)) 求导数,
Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1))
求导数,

人气：395 ℃　时间：2019-09-01 04:58:30

解答

1:y'=x*[loga(x^2+x-1)]'+loga(x^2+x-1)=x*(2x+1)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)=(2x^2+x)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)2:y'=(x+1)/[Ln2(x-1)]*[(x - 1)/(x + 1)]'=(x+1)/[Ln2(x-1)]*[(x+1)-(x-1...