(1)f[log2(1/3)]=f[-log2(3)]=-f[log2(3)]=-2^log2(3)=-3
(2)当x0,由于是奇函数,所以 f(x)=-f(-x)=-2^(-x)
从而解析式为
┍ 2^x x>0
f(x)= | 0 x=0
┕ -2^(-x) x