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(x+y)(x²+y²)(x-y)(x的四次方+y的四次方)
人气:293 ℃ 时间:2020-02-03 05:05:43
解答
原式=(x+y)(x-y)(x^2+y^2)(x^4+y^4)
=(x^2-y^2)(x^2+y^2)(x^4+y^4)
=(x^4-y^4)(x^4+y^4)
=x^8-y^8
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