(1)若不等式ax²-3x+2>0的解集为{x|xb}那么x=1,x=b是方程ax²-3x+2=0的解那么a-3+2=0所以a=1所以x²-3x+2=(x-1)(x-2)=0故b=2即a=1,b=2(2)(c-x)/(ax+b)>0(c-x)/(x+2)>0(c-x)(x+2)>0(x-c)(x+2)...