(1)sin（2x-π/3）∈[-1,1] ∴2sin（2x-π/3）∈[-2,2]即函数值域是[-2,2](2)周期T=2π/2 =π(3)由-π/2 +2kπ《2x- π/3《π/2 +2kπ得-π/12 +kπ《x《5π/12 +kπ∴函数的单调增区间是[-π/12 +kπ,5π/12 +kπ] ...