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化学
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将1.721gcaso4.xH2o加热,使其失去全部结晶水,这是剩余固体物质的质量是1.361g,计算1mol此结晶水合物中所含结晶水的物质的量?
人气:171 ℃ 时间:2020-04-02 04:11:15
解答
CaSO4的质量为1.361g,结晶水的质量==1.721-1.361==0.36g,
n(CaSO4)=1.361/136=0.01 mol;n(H2O)=0.36/18=0.02 mol,
CaSO4.xH2O==CaSO4 + x H2O
1 x
0.01 0.02
所以x=2 mol
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