原式=x²(x-y)-(x-y)
=(x-y)(x²-1)
=(x-y)(x+1)(x-1)从第一步到第二步是怎样得的呢？y-x=-(x-y)采纳吧那从x²(x-y)-(x-y)=(x-y)(x²-1)这一步是咋得的呢？请详细解说一下你打算采纳我吗？嗯提取公因式(x-y)马上采纳吧