如果是
(2x+k-1)/2=(1-x+k)/3
6x+3k-3=2-2x+2k
x=(5-k)/8=2 k=-11
如果是
(2x+k)/2-1=(1-x)/3+k
6x+3k-6=2-2x+6k
8x=8+3k
x=1+3k/8=2
x=8/3
如果是(2x+k)/2-1=(1-x+k)/3
6x+3k-6=2-2x+2k
8x=8-k
x=1-k/8=2
k=-8