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X^2-y^2-x-y=0 和4x^2-y^2+2y-1=0 的方程组怎么解
人气:472 ℃ 时间:2020-04-09 01:33:19
解答
X^2-y^2-x-y=0.(1)4x^2-y^2+2y-1=0 .(2)根据(1):(x+y)(x-y)-(x+y)=0(x+y)(x-y-1)=0x+y=0.(3)或x-y-1=0.(4)根据(2):(2x)^2-(y-1)^2=0(2x+y-1)(2x-y+1)=02x+y-1=0.(5)或2x-y+1=0.(6)(3),(5)联立方程,解得:x=0,y=...
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