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y=5x-1/4x+2,求值域
人气:328 ℃ 时间:2020-03-29 06:52:06
解答
y=(5x-1)/(4x+2)
=(5x+5/2-7/2)/(4x+2)
=(5x+5/2)/(4x+2)-7/[2(4x+2)]
=5/4-7/(8x+4)
因为7/(8x+4)不等于0,
y=5/4-7/(8x+4)不等于5/4
所以
y=(5x-1)/(4x+2)的值域为y不等于5/4
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