设p(x1,y1)当A=0时,可解出x1=x0,y1=(-2c/B)-y0;当B=0时,可解出x1=(-2c/A)-x0,y1=y0当AB不等于0时因为是对称点,线段中点在直线上：A(x1+x0)/2+B(y1+y0)/2+c=0垂直：(y1-y0)/(x1-x0）*（-A/B）=-1解出x1=-(2cA+ABy0-x0...