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将下列式子因式分解:x-x2-y+y2=______.
人气:135 ℃ 时间:2020-03-30 14:44:48
解答
原式=(x-y)-(x2-y2
=(x-y)-(x+y)(x-y)
=(x-y)(1-x-y),
故答案为:(x-y)(1-x-y).
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