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x'3+x'2+8y'3-4y'2因式分解
人气:478 ℃ 时间:2020-05-20 06:59:51
解答
x'3+x'2+8y'3-4y'2
=(x^3+8y^3)+(x^2-4y^2)
=(x+2y)(x^2-2xy+4y^2)+(x+2y)(x-2y)
=(x+2y)(x^2-2xy+4y^2+x-2y)
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