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x^2-y^2+2x-4y-3因式分解
人气:408 ℃ 时间:2020-04-09 09:57:19
解答
x²-y²+2x-4y-3
原式=x²+2x+1-y²-4y-4
=﹙x²+2x+1﹚-﹙y²+4y+4﹚
=﹙x+1﹚²-﹙y+2﹚²
=﹙x+1-y-2﹚﹙x+1+y+2﹚
=﹙x-y-1﹚﹙x+y+3﹚
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