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将(x^2+10x+4)(x^2+10x-2)-55因式分解(过程)
人气:304 ℃ 时间:2020-06-17 13:10:15
解答
(x^2+10x+4)(x^2+10x-2)-55
=(x^2+10x)^2+2(x^2+10x)-63
=(x^2+10x+9)(x^2+10x-7)
=(x+1)(x+9)(x^2+10x+25-32)
=(x+1)(x+9)(x+5+4√2)(x+5-4√2)
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