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已知:x+y=5,x²+y² =11,求代数式x³y-2x²y²+xy³的值
人气:164 ℃ 时间:2019-10-31 14:32:35
解答
x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy(x-y)²
=xy[(x+y)²-4xy]
=5x(11²-4x5)
=5x101
=505
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